‘The Blacklist’ season 4 spoilers: Can Megan Boone’s Liz infiltrate all-female group of assassins?
If one of things that you enjoy the most about “The Blacklist” is seeing an opportunity to watch some notable criminals be taken down a notch or two, you may be happy to know that it could be coming up within the first batch of episodes airing in the new year. While it’s hard to determine an episode’s tone for certain until they air, early indications about the upcoming installments suggest that we could be seeing something a little bit more in line with what was out there during the first season of the show. More Blacklisters!
So let’s get to what we mentioned in the title for this article, since we can see this being a big reason why so many people are going to be excited for one upcoming episode in particular. Per NBC, on the upcoming January 19 episode entitled “The Harem,” we’re going to see Liz Keen (Megan Boone) doing what she can to impress the leader of this aforementioned all-female group of assassins, played by Jill Hennessy. If she can do this, then she may be able to really disguise herself as a member of the group and be able to properly dive into the next heist all the more effectively.
As for some of the other characters in this episode…
Red – Apparently, something is going to go terribly wrong in his operation over the course of the episode, and he’ll have to work overtime in order to fix it. (If you missed it, vote for James Spader as one of our biggest Golden Globe snubs of the year.)
Tom Keen – Meanwhile, we’re going to see him become more and more accustomed to being a father, which probably knowing this show means that the hammer is probably going to drop soon that takes him away from the show. We find it interesting at this point that Ryan Eggold has basically kept his status as full-time cast member on this show so far, even if he does have “The Blacklist: Redemption” coming out shortly. Our feeling is that he’ll probably be gone from most of the remaining “Blacklist” episodes this season once that starts.